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proofreading sketch -which by definition is a picture in words that are matterless- pales in its job compared to verifying proof

$proofreading sketch -which by definition is a picture in words that are matterless- pales in its job compared to verifying proof | SUPPOSE WE BELIEVE THERE IS A BIJECTIVE BETWEEN A COMPREHENSIVE LIST OF REALS {(1,0]} AND THEIR FOURTH ROOTS AS NEGATIVE REALS? IT'S RATHER EASY TO USE THE DIAGONAL METHOD TO SHOW THAT THE RAVENOUSLY ENDLESS STRING OF ONES WITH A MINUS SIGN IS NEVER A SQUARE ROOT OF THE VENOMOUSLY ENDLESS STRING WITH A PLUS SIGN. THEREFORE THIS FOURTH ROOT AS A BRUTALLY ENDLESS STRING OF ONE'S [ESO] ROOT OF AN IMAGINARY IS A COMPLEX VALUE. THAT MAKES IT SEEMINGLY ABSENT FROM OUR BIJECTIVE. HOWEVER THE SQUARE ROOT OF ZERO AS CONCEIVABLY A ±ROOT OF {0⁕2} ALLOWING {<I+1=-I-1>⇒<I=1>} IS ALSO AN ISSUE. SO WE TAKE AS LEMMA THAT ZERO MUST RESIDE IN THE DIAGONAL. RUNNING BACKWARDS THOUGH WITH A RAVENOUS ESO MINUSING WITHIN A COMPREHENSIVE LIST OF NEGATIVE REALS {(¬-0,$]} AND SQUARING? THE VENOMOUS ESO IS NEITHER HERE A SQUARE OF THE RAVENOUS ESO! SO THE RESULT MUST BE BIJECTIVELY A LISTING OF POSITIVE REALS INCLUDING ZERO WITH THE VENOMOUS ESO RELEGATED TO THE DIAGONAL. SO TO SHOW THAT THE VENOMOUS ESO SQUARE ROOT EQUALS MINUS ZERO, SYMMETRICALLY NICE, WOULD SET CANTORIAN THEORY ADRIFT. THIS WOULD BE THE SAME AS SHOWING THAT MINUS ZERO IS THE SQUARE OF THE RAVENOUS ESO. . "IF I BELIEVE THE TERRIBLY WRONG THING WITH THE WORLD IS THAT THE TERRIBLE WRONG THING WITH THE WORLD IS WHAT NOBODY BELIEVES IF THE TERRIBLE WRONG"; WAT SUPERVENING RUSSELL'S PARADOX UPSIDE DOWN??? PROOF: TAKE {(∞-1)/(∞)⁕(∞-∞)⁕(I^2)=(∞-1)/(∞)⁕(∞-∞)⁕(I^2)} IMPLIES CLASSICALLY AS IN ∞/∞=(1/N)=(N) {(∞-1)⁕(1/N-N)⁕(I^2)=(∞-1)⁕(1/N)-N)⁕(I^2)} IMPLIES {(∞-1)⁕(N-1)⁕(I^2)=(∞-1)⁕(N-1)⁕(I^2)} IMPLIES IF N'S LIMIT IS ITSELF INFINITY {¥⁕(I/I)=¥⁕(I/I)}. THIS MEANS IF OUR LIST {{($⁕(I^0),¬0⁕(I^0)]} AND} HAD AN IMAGINARY IDENTITY FOR ONE THEN OUR MISSING RAVENOUS ESO RESULTS IN THE FOURTH ROOT BIJECTIVE AS {(√(I⁕$)⁕((√I⁕√(I+1))/((-)⁕√(I+1))} IMPLIES {(√(I⁕¥)⁕(-√I)}. UNEXPECTEDLY OUR FOURTH ROOT LACKS {$} NOW ALSO. IF THE INFINITE ROOT THEN BY EXTENSION OF AN INFINITE IMAGINARY UNITY IS ALSO ABSENT? WE MODIFY OUR ODD INTEGERS IN THE ACTUAL COUNT OF REALS TO COUNT AS {N⁕(I^N)/{N⁕(I^N)} UNITIES. NOW WHEN AN INFINITE VENOMOUS ESO OCCURS AKA {11111.....11111.0} TO ATTEMPT COUNTING THE VENOMOUS ESO?? THAT VALUE CANNOT BE EXPRESSED AS EVEN THE FRACTIONAL {((-1)⁕11111.....11111.11111.....)/ ((-1)⁕11111.....11111.11111*****)} WHICH IS IMPORTANT IN CASE WE CLAIM THAT THE VENOMOUS ESO IS AN INFINITE SUBSETTING OF ITSELF. | image tagged in hogwarts | made w/ Imgflip meme maker$