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They're The Same Picture

by JohnGolden2

98 views, 4 upvotes, 1 comment

it takes a village and I found a ghost town

by anonymous

157 views, 5 upvotes

Far Along The Derivation We Remember Mentally Making The Right Move: √2/√2-2⁕1/∞⁕√2/√2...Coffee Ice Cream Break

$Far Along The Derivation We Remember Mentally Making The Right Move: √2/√2-2⁕1/∞⁕√2/√2...Coffee Ice Cream Break | WITH LEMMA: {(∞-1)/∞} ± [{(∞-1)/∞}/∞] = ∞*{(∞-1)/∞} PROVIDING CYCLIC {(1-∞)/∞}^(1/2) = {(∞-1)/∞}^(1/4) = {(1-∞)/∞}; SHOW THAT GELFOND-SCHNEIDER CONSTANT WHICH IS DEFINED AS 2^(√2) DERIVES √2/√2 = -0 VIA (-0)^∞=(-0)⁕(-0)^(∞-1) AS (-0)^{∞/(∞-1)}=0 AS (0)^{(∞-1)/∞}=-0 AS (1-1)^∞ = 2⁕√2/√2 - 2⁕√2/√2 AS (∞-∞)⁕(1+1)/(1+1)=√2/√2 - √2/√2 AS (2⁕∞/2)-(2⁕∞/))=√2/√2 - √2/√2 AS √2/√2 + (2⁕∞/2)=√2/√2 + (2⁕∞/2)) AS √2/√2 + ∞⁕(√2⁕/√2)^2=√2/√2 + ∞⁕(√2⁕/√2))^2 AS √2/√2⁕ + (√2⁕/√2+ ((√2⁕/√2)-(1/∞)⁕((√2⁕/√2)))^2= √2/√2 +((√2⁕/√2)-(1/∞)⁕((√2⁕/√2)))^2 AS √2/√2 +1- 2/∞ + 1/∞^2 = √2/√2 +1- 2/∞ + 1/∞^2 AS √2/√2 +(1+1/∞)^2 = √2/√2 +(1+1/∞)^2 AS √2/√2 =√2/√2; THEREFORE DIAGONAL OF POSITIVE REALS LIST AS '1111111.....11111' EQUALS DIAGONAL OF NEGATIVE REALS LIST AS '00000.....00000"; WHICH IS NICELY EXPLAINED BY INFORMATION THEORY IN THAT THE GREATER HOMOGENEITY OF A STRING OF DIGITS THE LESS INFO IT SUPPLIES. SO IN SHORT CANTOR DIAGONALS SYMMETRICALLY PROVIDE ACCORDING TO INFORMATION THEORY NO INFORMATION TO BE COUNTED BIJECTIVELY WHICH IS THE LITERAL OPPOSITE OF UNRESTRICTED COMPREHENSION CONCERNS | image tagged in memes,expanding brain | made w/ Imgflip meme maker$