the answer is \(x=\frac{1+\sqrt{61}}{10}\quad \text{and}\quad x=\frac{-1-\sqrt{13}}{6}\)
yes I serach it up and this
but it more
4x=0
x=0

enough to be on this platform but I'm not going to tell bc of privacy reasons.

yes

immm more than 10

no I'm not