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by anonymous
736 views, 3 upvotes, 2 comments
![it's nice to post less, more sporadically | TRYING; TRYING; TRYING; TRYING; GELFOND–SCHNEIDER CONSTANT OR
HILBERT NUMBER MAY BE THE MOST
FASCINATING CASE OF SCHOLARLY
PRESUMPTIVENESS; IT JUST LOOKS
WRONG SOMEHOW TO BELIEVE THAT
TWO RAISED TO THE SQUARE ROOT OF
TWO IS IRRATIONAL. IF SO THEN THIS
ALSO ▣(√2)^(√2)^2▣ IS THAT SAME
CONSTANT AND ALLOWS FOR A NEAR
INFINITE TITRATION. UNTIL TWO IS
RESTORED TO ITS BASE AND THEN
INFINITE. NOW LET US SAY THAT THE GF
CAN MULTIPLY TIMES ITSELF AN INFINITY
OF TIMES. DOING SO ALLOWS US TO
IMAGINE THAT THOSE SQUARE ROOT OF
TWO POWERS COULD BE EITHER POSITIVE
OR NEGATIVE. HOLD UP! THAT MEANS
THAT ONE OF OUR GELFONDISH FRACTIONS
IS UNLISTABLE AND THEREFORE
UNCOUNTABLE. THE FUNNY THING
THOUGH IS THAT THE UNLISTABLE VALUE
MAY AS WELL BE THE GF CONSTANT
ITSELF; . IF GF'S PRODUCTS ARE EQUATED TO
GF'S PRODUCTS THEN FOR THAT
TO EXHIBIT UN- COUNTABLENESS,
BIJECTIVELY, ONE SIDE MUST LIST LIST
TO AN INFINITE ODD COUNT AND THE
OTHER SIDE TO AN INFINITE EVEN
AND THUS THE EQUATION ITSELF
EXHIBITS THE SENSE OF UNLISTABILITY.
SO THERE STILL THE GF CONSTANT IS
UNLISTED. YET TAKING THE RATIO OF
THE ODD PRODUCT AND THE EVEN
PRODUCT WOULD VARIOUSLY BE PLUS
OR MINUS INFINITY PLUS OR MINUS
ONE OVER INFINITY. BY DEFINING
ONE OF THOSE NUMBERS WHICH IS
MEANINGLESS AND WITHOUT
MAGNITUDE SO DIRECTLY AKA
▣√2/√2▣ THE PROOF OF
IRRATIONALITY IS SUSPECT. THAT IS
▣2^[√2/√2]=2⇒2^(∞-1)=2^∞▣
WHICH CANNOT BE. | image tagged in tagagagagagagagagafafafafafadada | made w/ Imgflip meme maker](http://i.imgflip.com/9u9izh.jpg)
