blck wht shadow flop variant on neon background...WITH EASTER EGG HOMAGE TO THE RIPPING GIANTS WE WRESTLED

IF WE TAKE THE ZERO POWER OF SQUARE OF TWO RAISED TO INFINITY EQUALS ITSELF THERE IS A BIZARRE RAMIFICATION. IT HAS TO DO WITH UNCOUNTABLE SQUARE ROOTS IN THE IMAGINARY. THAT IS WE HAVE TAKEN PLUS OR MINUS THE IMAGINARY ADDED TO ONE OVER ITSELF RAISED TO INFINITY. AND BY DIAGONALIZING THE PLUS OR MINUS ONE FACTORS THINGS RAMIFY IN A WAY THAT CAN BE INTRIGUING ALSO, IF HANDLED PROPERLY. SO LET'S SAY THAT THIS EQUALITY IS ALSO SQUARED AND THAT WE HAVE A FORM OF TWO RAISED TO INFINITY OVER ITSELF OVER ITSELF EQUALS INFINITY OVER INFINITY OVER INFINITY OVER INFINITY. THAT IS RESTATED WHERE THE RIGHT HAND SIDE HAS OUR UNCOUNTABLE POWERS OF THE SQUARE ROOT OF TWO TO A ZERO POWER AND AGAIN TO ANOTHER ZERO POWER. WHAT DOES THIS ACCOMPLISH? LET'S BREAK ANY ONE OF THOSE NUMERATORS OR DENOMINATORS DOWN! ⫷2^∞=∞⁕(±√2)∞⫸ IS THUSLY KNOWN TO HAVE AN UNCOUNTED FACTOR OF ⫷(√2^∞)⫸. WHAT WE DO WITH THAT UNCOUNTED FACTOR IS HAVE IT BE EXISTENT ON THE LEFT HAND SIDE OF THE BREAKDOWN SO ⫷(2^∞)⁕(√2)^∞=∞⁕ (±√2)∞⫸ IS FULLY ACCOUNTED FOR OR NOT A PRODUCT WITH UNCOUNTABLE FACTORS FOR. THUSLY IF WE BUILD UP FROM THERE WE CAN PROVIDE ⫷ {∞⁕(√2^)^∞}◍◪ —————◍— {∞⁕(√2^)^∞}◍◪ —————=— {∞⁕(√2^)^∞}◍◪ —————◍— {∞⁕(√2^)^∞}◍◪ ⫸ WHERE THOSE VERTICLELY SCORED CIRCLES ARE JUST FORMATTING MARKS TO BE ABLE TO TYPE OUT. WHAT'S NEED NOW IS MAKING SURE OUR CONSTRUCTABLE SYNTHESIS DOES NOT ALLOW UNRESTRICTED COMPREHENSION WHEN OR FACTOR LISTS ARE REMOVED. SO WE COMMIT TO MAKING SOME OF OUR INFINITE POWERS OF TWO SQUARE ROOT OF TO BE INFINITE PLUS ONE POWER. AT LEAST MOMENTARILLY, WHERE THE LEFT SIDE BEING EQUALED TO ITSELF HAS SOME FACTORS AS SQUARE ROOTS OF TWO SHIFTED AROUND. ⫷ {∞⁕(√2^)^[∞+1]}◍{∞⁕(√2^)^[∞+1]} ———————◍———————— {∞⁕(√2^)^[∞]}◍{∞⁕(√2^)^∞} ———————=————————— {∞⁕(√2^)^∞}◍{∞⁕(√2^)^[∞+1]} ———————◍———————— {∞⁕(√2^)^[∞-1]}◍{∞⁕(√2^)^∞} ⫸; TO BALANCE SPACE AND CLARITY AND A RATIONAL WE RETAIN ONE OF THE OVER-INFINITE POWERS IN UPPER FRACTIONS ON LEFT-SIDE & RIGHT-SIDE. THOSE UPPER FRACTIONS CAN BE TERMED AN IMPROPERLY INFINITE FRACTIONS. THE ARE UNCOUNTABLY FACTORED AND ARE ALLOWED TO COLLAPSE PEACEFUL BACK INTO THE UNIT IDENTITY FROM WHICH THEY MUST BE DERIVED. THIS KEAVES ONCE A UNIT RATIO OF ⫷(√2)/(√2)⫸ IS FACTORED FROM THE RIGHT-SIDE LOWER ⫷(√2/√2)= {(∞-1)/∞}⁕(∞^2/∞^2)⫸. OR ⫷√2^0=1-1/∞⫸ AS SIGNIFICANT RESULT, GLEEFULLY. THE PREVIOUS SENTENCE'S EQUATION CAN THEN BE USED FOR DISPUTATIOUS INTEPRETATION OF THE GELFOND-SCHNEIDER CONSTANT. OUR RESULT ALSO MEANS THAT ⫷{(∞-1)/∞}={(∞-1)/∞}^[2]⫸ YET OFCOURSE NOT ⫷2^0={(∞-1)/∞}⫸. SO ⫷√2^[1/4]⁕∞⁕{(∞-1)/∞}= √2^[1/4]⁕∞⁕{(∞-1)/∞}⫸ WHERE THAT (∞/∞) MUST NOT BE MESSED WITH LEADS TO PARTIALLY THROUGH ⫷√2^[2/2]=√2^[2/2]⫸ AND ⫷√2^[√2/√2]^[√2/√2]= √2^[2/2]^[√2/√2]⫸ AS ⫷√2^2^[√2/√2]=√2^2^[2/2]⫸ AND ⫷2^[√2/√2]=2^[2/2]⫸ PROVIDING EVENTUALLY LUCKILLY ON THE ADJUSTED SIDE ⫷(2/2)^[(∞-1)/∞]⫸ WHICH IS ANOTHER NICE WAY TO SAY A UNITY OF ONE OVER ONE WHICH IS OFCOURSE OUR EARLIER CANCELLED DISUNITY OF ⫷(2/2)^[(∞+1)/∞]⫸ IN TECHNICALLY PROPER NON-INDETERMINATE ONE TO INFINITY. SO NOW ⫷∞⁕(√2)^0=∞⁕(√2)^0⫸ IS TAKEN AS ⫷(∞^2)⁕(√2)^2=1/{(∞^2)⁕(√2)^2⫸† AND THEN SQUARE ROOTED FINALLY ⫷(∞⁕√2)= 1/(∞⁕√2)⫸. GELFOND-SCHNEIDER REARRANGED AND POWERED TO INFINITY OVER INFINITY (WHICH WONT TURN OUT TO BE INDETERNINATE FOR TWO IF OBVIOUSLY WE SUBSTITUTE SQUARE ROOT OF TWO SQUARED THAT IS THE SISTER TO GELFOND-SCHNEIDER): ⫷2^[∞/∞]^[√2/√2]=2⫸. SUBSTITUTING IN ⫷4^[∞⁕√2]=2⫸ YET ALSO ⫷(2^2)^[1/{∞⁕√2}]=4^[1/2]⫸. LOOKS LIKE ⫷2^[2/∞]⁕2^[√2]=2^[√2]⫸ AS ⫷2^[1/∞]⁕2^[√2]=(2^∞)⁕2^[√2]⫸. THAT WAS RUSHED IN LAST STEPS YET WE GET THE IDEA? AND TO CONCEIVE AS BEST WE CAN ON OUR OWN, RAISE UP TO SOME ACTUALLY OVER INFINITE POWER AND MAGICALLY, ⫷2^[∞]⁕2^[√2]= (2^∞^∞)⁕2^[√2]⫸. WE KNOW INFINITIES TIMES INFINITIES ARE NEGATIVE INFINITIES -DON'T ASK- THUS THE PROOF IS DONE. ⫷2^[∞]⁕2^[√2]=2^[-∞]⁕2^[√2]⫸.■; WHAT SEQUEL IF RAINMAN [W] TOOK CARE BABBIT