γ:🔊→R; α↦f(α∣
z
^
)=
∫
🌌
​
f(
z
^
∣🌎)P(🌎)d🌎
f(
z
^
∣α)P(α)
​

\alpha_{\mathsf{MAP}}(\hat{\mathbf z}) = \argmax_{\alpha \in 🔊} \gamma(\alpha)α
MAP
​
(
z
^
)=argmax
α∈🔊
​
γ(α)

?

🤣😂

He looks homeless and rich at the same time

Eat nuts