MAY THE; THERE ARE TWO WAYS TO SOLVE THIS QUESTION. THE FASTER WAY IS TO MULTIPLY EACH SIDE OF THE GIVEN EQUATION BY AX−2 (SO YOU CAN GET RID OF THE FRACTION). WHEN YOU MULTIPLY EACH SIDE BY AX−2, YOU SHOULD HAVE:
24X2+25X−47=(−8X−3)(AX−2)−53
YOU SHOULD THEN MULTIPLY (−8X−3) AND (AX−2) USING FOIL.
24X2+25X−47=−8AX2−3AX+16X+6−53
THEN, REDUCE ON THE RIGHT SIDE OF THE EQUATION
24X2+25X−47=−8AX2−3AX+16X−47
SINCE THE COEFFICIENTS OF THE X2-TERM HAVE TO BE EQUAL ON BOTH SIDES OF THE EQUATION, −8A=24, OR A=−3.
THE OTHER OPTION WHICH IS LONGER AND MORE TEDIOUS IS TO ATTEMPT TO PLUG IN ALL OF THE ANSWER CHOICES FOR A AND SEE WHICH ANSWER CHOICE MAKES BOTH SIDES OF THE EQUATION EQUAL. AGAIN, THIS IS THE LONGER OPTION, AND I DO NOT RECOMMEND IT FOR THE ACTUAL SAT AS IT WILL WASTE TOO MUCH TIME. BE WITH YOU