WHEN YOU KNOW THAT IF TWO TRIANGLES HAVE TWO SIDES EQUAL TO TWO SIDES RESPECTIVELY, AND HAVE THE ANGLES CONTAINED BY THE EQUAL STRAIGHT LINES EQUAL, THEN THEY ALSO HAVE THE BASE EQUAL TO THE BASE, THE TRIANGLE EQUALS THE TRIANGLE, AND THE REMAINING ANGLES EQUAL THE REMAINING ANGLES RESPECTIVELY, NAMELY THOSE OPPOSITE THE EQUAL SIDES. BUT YOU JUST CAN'T PROVE IT