DAILY MATHS / PHYSICS.
(I'LL SOLVE / EXPLAIN SOMETHING EVERY DAY)
DAY 1; I HAVE AN PHYSICS EXAM TOMORROW. I'LL DO A QUESTION ABOUT THE SUBJECT: ENERGY
YOU HAVE A PAN WITH 1 L WATER AT ROOM TEMPERATURE (20°C) YOU WANT TO HEAT THE WATER TO 100°C.
(ASUME THE PAN IS MADE OF IRON)
HOW MUCH ENERGY DO YOU NEED?
GIVEN INFO:
T(START) = 20°C
T(END(WATER)) = 100°C
c(WATER) = 4.18 g/(J*°C)
c(IRON) = 0.46 g/(J*°C)
V = 1L
RHO ~= 1 (DON'T KNOW BY HEART)
DELTA T = 100 - 20 = 80°C
CALCULATION:
Q = m * c * (delta)T
RHO = m / V
m = RHO * V
m = 1 * 1 = 1 kg = 1000 g
Q = 1000 * 4.18 * 80 ~= 3300000
(DON'T HAVE CALCULATOR RIGHT NOW)
CONCLUSION:
(IF YOU HAVE READ THIS ALL, YOU'RE GREAT)
THE ENERGY REQUIRED TO HEAT THE WATER TO 100°C IS 330000
Caption this Meme