how do i prove that ABK = DCK help

why don't you just flip dck

i have to use one of the theorems
oh btw KB = KC and angle ABK = angle DCK

vertical angles. the two corners that are touching are congruent angles, which makes them congruent through angle side angle

Opposite angles of K are equivalent

<CKD ≈ <BKA
∆CDK ≈ ∆ABK by AA

whats AA

Oh wait no hold up

KB = KC and < ABK = < DCK

Had a brain moment

ASA I meant