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answer

answer | image tagged in bda announcement temp | made w/ Imgflip meme maker
114 views 4 upvotes Made by anonymous 2 years ago in MS_memer_group
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26 Comments
[deleted] M
1 up, 2y,
1 reply
x²= UwU~
[deleted]
1 up, 2y,
1 reply
ye
[deleted] M
1 up, 2y,
1 reply
OwO
[deleted]
1 up, 2y,
2 replies
-owo-
[deleted] M
1 up, 2y,
1 reply
:3
[deleted]
1 up, 2y,
1 reply
^w^
[deleted] M
1 up, 2y,
1 reply
-w-
[deleted]
0 ups, 2y,
1 reply
>wO
[deleted] M
0 ups, 2y,
1 reply
UwU
[deleted]
0 ups, 2y,
1 reply
-w-
[deleted] M
0 ups, 2y
uwu
[deleted] M
1 up, 2y,
1 reply
[deleted]
1 up, 2y,
1 reply
i finish my homework lol
[deleted] M
0 ups, 2y,
1 reply
bullshit bruh i see you on here every 3 minutes or something
[deleted]
0 ups, 2y
its sunday

why tf do you think i have homework
[deleted] M
1 up, 2y
ok bruh i might be failing algebra but if yall seriously dont get this shit im jumping off a skyscraper
0 ups, 2y
i'm just gonna say like 0 or smth
0 ups, 2y,
1 reply
16?
[deleted]
0 ups, 2y
no
0 ups, 2y,
1 reply
3+3x
[deleted]
0 ups, 2y
well you're not wrong
[deleted]
0 ups, 2y,
1 reply
Why am I solving for x^2? I actually don't know what the final exact answer is, because of that.

I completed the square to solve this.

So I'm left with x = 1.5 ± sqrt(5.25). Do I solve for the individual numbers and then square them, or do I square both sides straight from that step?

Let a be equal to 1.5 + sqrt(5.25), and b be equal to 1.5 - sqrt(5.25). Thus, x=a and x=b. So if I square them, then I get a*a and b*b. But if I do the method where I square both sides, I get this:

[x = 1.5 ± sqrt(5.25)]^2.

I can't distribute the exponent, so we expand it:

(x = 1.5 ± sqrt(5.25))(x = 1.5 ± sqrt(5.25))

Either one could be a or b, so my answers are a*a, b*b, or a*b. (b*a = a*b, the commutative property of multiplication)

I plugged the calculation into desmos, and a=3.79128784748 and b=-0.791287847478, approximately. If I square them, I get a^2=14.3738635424 and b^2=0.626136457566. And quite nicely, a*b = -3.

Now, admittedly, the square root a*b is not a solution to the equation (it's imaginary). However, we're looking at what x^2 is, which is what made this problem so weird in the first place. And technically -3 fits that criteria, as since x=a and x=b, x^2 can be equal to a*b.

I really don't care if you give me a nerd emoji or not, but I'd like it if someone could tell me if one way is more right than the other or something.

Man I really I hope I didn't mess up something stupid.
[deleted]
0 ups, 2y,
1 reply
did you not think of solving for x, then squaring?
[deleted]
0 ups, 2y,
1 reply
Either I formatted that terribly, or you didn't read it. (I don't blame you)
Yeah I did that. It's the first method I describe.
[deleted]
0 ups, 2y,
1 reply
oh
[deleted]
0 ups, 2y
However, here's the interesting part (I'm restating myself here), -3 could be an answer. Say the solutions are a and b, x=a and x=b. Then x^2= aa and x^2 = bb. So the answers are two irrational numbers.

However, we could substitute and get x^2 = ab, which happens to be -3. Sorry, I just find this fascinating.
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