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-giraffe- | CAN SOMEONE PLEASE HELP ME WITH ONE MATH QUESTION WITH PARABOLAS | image tagged in -giraffe- | made w/ Imgflip meme maker
84 views 5 upvotes Made by anonymous 11 months ago in MS_memer_group
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25 Comments
1 up, 11mo,
1 reply
i think these people are too dumb for that. I could help but am gonna choose not to.
[deleted]
0 ups, 11mo
Morgan Freeman True | image tagged in morgan freeman true | made w/ Imgflip meme maker
0 ups, 11mo,
1 reply
I can help but I might get some things wrong
[deleted]
0 ups, 11mo,
3 replies
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its always set to whats on the graph
0 ups, 11mo
The expression is in vertex form, which makes the properties of the parabola easy to discern. The transformations entailed in g(x) are as follows:
A vertical compression by a factor of 1/3, meaning every x value gets their y value divided by 3;
A horizontal shift 6 units to the right; and
A vertical shift 1 unit up.
Thus the vertex should be (6,1) (ah_furry is correct on this).

To properly graph the points found on g(x), you have to draw a table that contains the points found on the parent function, f(x) = x². The parent function's table is as follows:
[(-3,9), (-2,4), (-1,1), (0,0), (1,1), (2,4), (3,9)]
Vertical compressions and shifts both affect the y-values, while horizontal shifts affect the x-values. Therefore, you would have to add 6 to every x-value (x + 6) and add 1 to every y-value divided by 3 (y/3 + 1).
The resulting graph should be:
[(3,4), (4,7/3), (5,4/3), (6,1), (7,4/3), (8,7/3), (9,4)]
0 ups, 11mo,
1 reply
1/3(0-6)^2 + 1
= 1/3(-6)^2 + 1
= (1/3)36 + 1
= 12 + 1
= 13

One of the coordinates is (0,13)
[deleted]
0 ups, 11mo,
2 replies
13 aint even on the graph💀
0 ups, 11mo
Obviously.

Now plug 6 instead of 0
0 ups, 11mo,
1 reply
the funny thing is that 0,13 is on the graph
[deleted]
0 ups, 11mo,
1 reply
how, it only goes up to 10
0 ups, 11mo
on the parabola I mean.
0 ups, 11mo,
1 reply
the vertex is (6,1)
[deleted]
0 ups, 11mo,
1 reply
what about the 1/3
0 ups, 11mo,
1 reply
thats the slope of the graph.
[deleted]
0 ups, 11mo,
1 reply
so it will be up 1, right 3?
0 ups, 11mo,
1 reply
Yeah i think also the points (3,4) and (9,4) will be in the graph if that helps
[deleted]
0 ups, 11mo,
1 reply
where's you get (9,4) from
0 ups, 11mo,
1 reply
imma be honest, I used desmos calculator to find the graph. but trust me, those points are on the parabola
[deleted]
0 ups, 11mo,
1 reply
im f**ked then. im using khan academy
0 ups, 11mo
bacically just used what I said.
[deleted]
0 ups, 11mo,
1 reply
I may not have a brain, gentlemen, but I can try
[deleted]
0 ups, 11mo
refer to what i said to ah_furry
0 ups, 11mo,
1 reply
Tell me
[deleted]
1 up, 11mo,
1 reply
refer to ah_furry
0 ups, 11mo
K
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CAN SOMEONE PLEASE HELP ME WITH ONE MATH QUESTION WITH PARABOLAS