formal way of math

Let a = (3^2) - 7
Let b = (((8^a) + (a^8))/20) - 6
let c = (b^2a * (a/b))
let d = (c^5)/(10^2)
let e = (d/b)/a
Solve for x: (((3^(e - a)) - (log (bd^e)))/6) - x = -1

(MATH MY GREATEST ENEMY) IM SCARED

my formal: square root of 16