Uh uh
So if you take the first 2 and add a variable “x” and you take the second 2 and add “y” we get 2x + 2y = z, which is equivalent to z - 2y = 2x
Taking that and dividing it by 2 you get z/2 - y = x
So we know x = z/2 - y
And if we add Sigma to signify the sum (x) and substitute we get Σ = z/2 - y, because we eliminated the x
We know x was equal to 2 therefore we divide the 2 in z/2 by x to get z/(1/2x)
So we have Σ = z/(1/2x) - y
We now have to multiply by 2 to get rid of the 1/2
2Σ = 2 x (2(zx - y))
Which simplifies is 2Σ = 2 x 2zx - 2y
Combining like terms gives us 2Σ = 8zxy
Or dividing by 2 giving us Σ = 4zxy
If we subtract the zxy and eliminate it with substitution we have Σ = 4
Therefore the final answer is 4
