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Impossible...

Impossible... | < ∂grad(E)(k)/∂xj, h(k+1) > = - grad(E)(k)
x(k+1) = x(k) + h(k+1); Always has been. wait a second! Does that mean the hessian of a potential is equal to the Jacobian associated to the equilibrium equations??? | image tagged in memes,always has been | made w/ Imgflip meme maker
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< ∂grad(E)(k)/∂xj, h(k+1) > = - grad(E)(k) x(k+1) = x(k) + h(k+1); Always has been. wait a second! Does that mean the hessian of a potential is equal to the Jacobian associated to the equilibrium equations???